a=modN(n,k,[N])
n : | number | |
k : | divider | |
N : | Interval start |
a : | rest |
modN(1:6,3)
modN(1:6,3,2)
k=16:24 % startindices from 16 to 24 in a row list
k1=modN(k+1,numel(k),k(1)) % creates the lost if the following points23
This function, modN
, is an auxiliary procedure for array manipulation. It is designed to return values within a specified interval rather than the default range provided by the standard modulus operation.
The function modN
is defined to adjust the standard modulus operation. Instead of returning values between [0..k-1], it returns values within the interval [N..N+k-1]. This is achieved by the formula:
a = mod(n-N, k) + N;
Here's a step-by-step explanation:
N
from n
to shift the range of n
to start from zero.k
to get the remainder.N
back to shift the result into the desired interval [N..N+k-1].Here are some examples to illustrate the function's behavior:
modN(1:6, 3)
: This will return values within the interval [1..3].modN(1:6, 3, 2)
: This will return values within the interval [2..4].k=16:24
, the function modN(k+1, numel(k), k(1))
will create a list of points adjusted to the specified interval.This function is particularly useful in scenarios where a custom interval is needed for modulus operations, such as in certain classification tasks.
Algorithm explaination created using ChatGPT on 2025-08-18 23:22. (Please note: No guarantee for the correctness of this explanation)